Silver crystallises in the fcc unit cell. The edge length The unit cell is 409 pm. Find the radius of the silver atom.
Ans. a= 409 pm
for a Fcc unit cell
r=a/2√3= 409/2×1.414 = 144.5pm
Ans. a= 409 pm
for a Fcc unit cell
r=a/2√3= 409/2×1.414 = 144.5pm